1012 digital classification (20 points)

Given a series of positive integers, please classify the numbers as required and output the following 5 numbers:

• A 1 = the sum of all the even numbers in the number divisible by 5;
• A 2 = interleave and sum the remaining 1 numbers divided by 5 in the given order, i.e. calculate n 1 − N 2 + n 3 − n 4;
• A 3 = the number of the remaining 2 digits divided by 5;
• A 4 = the average of the numbers divided by 5 and remaining 3, accurate to 1 decimal place;
• A 5 = the largest of the remaining 4 digits divided by 5.

Input format:

Each input contains 1 test case. Each test case first gives a positive integer N of no more than 1000, and then gives N positive integers of no more than 1000 to be classified. Numbers are separated by spaces.

Output format:

For the given N positive integers, calculate A 1 ~ A 5 according to the requirements of the topic and output them in A row. Numbers are separated by spaces, but no extra spaces are allowed at the end of the line.

If one of the numbers does not exist, output N at the corresponding position.

Enter example 1:

13 1 2 3 4 5 6 7 8 9 10 20 16 18

Output example 1:

30 11 2 9.7 9

Enter example 2:

8 1 2 4 5 6 7 9 16

Output example 2:

N 11 2 N 9

#include <stdio.h>
#include <stdlib.h>
int a1(int n)
{
    if(n%10==0)
        return 1;
    else
        return 0;
}
int a2(int n)
{

    if(n%5==1)
        return 1;
    else
        return 0;
}
int a3(int n)
{
    if(n%5==2)
        return 1;
    else
        return 0;
}
int a4(int n)
{
    if(n%5==3)
        return 1;
    else
        return 0;

}
int a5(int n)
{

    if(n%5==4)
        return 1;
    else
        return 0;
}
int main()
{int n,i,count,count1,count2,count3,count4,sum=0,sum1=0,sum2=0,max=0,flag=1;
double average=0;
int a[1005];
count=0,count1=0,count2=0,count3=0,count4=0;
scanf("%d",&n);
for(i=0;i<n;i++)
{

    scanf("%d",&a[i]);

}
for(i=0;i<n;i++)
{
    if(a1(a[i])==1)
    {
        count++;
        sum+=a[i];
    }
    if(a2(a[i])==1)
      {  count1++;
        sum1+=a[i]*flag;
        flag=-flag;
    }
    if(a3(a[i])==1)
    {

        count2++;
    }
    if(a4(a[i])==1)
    {

        count3++;
        sum2+=a[i];
        average=sum2*1.0/count3;
    }
    if(a5(a[i])==1)
    {   count4++;
        if(max<a[i])
          max=a[i];
    }

}

    if(count==0)
        printf("N ");
    else
        printf("%d ",sum);
    if(count1==0)
         printf("N ");
    else
        printf("%d ",sum1);
    if(count2==0)
         printf("N ");
    else
        printf("%d ",count2);
    if(count3==0)
         printf("N ");
    else
        printf("%.1f ",average);
    if(count4==0)
         printf("N");
    else
        printf("%d",max);
    return 0;
}