There is often a requirement that enumeration constants are used in entity classes, but are serialized into json strings. The default is not the value I want, but the name, as follows

 

Class

@Data
public class TestBean {
    private TestConst testConst;

}

enumeration

@AllArgsConstructor
public enum TestConst {
    AFFIRM_STOCK(12),

    CONFIRM_ORDER(13),;
    
    @Setter
    @Getter
    private int status;


}

 

Default result: {"testfirst": "confirm" order "}

Expected result: {"testfirst": 13}

 

Three methods:

1. Using jackson, this is the simplest

2. If FastJson is used, enumeration class inherits JSONSerializable

3. This method specifies the demultiplexer in the entity class. (only the third method can address serialization and deserialization at the same time)

 

jackson method

//Add this annotation to the get method of the enumeration
@JsonValue
public Integer getStatus() {
    return status;
}

        TestBean form = new TestBean();
        form.setTestConst(TestConst.CONFIRM_ORDER);


        ObjectMapper mapper = new ObjectMapper();

        String mapJakcson = null;
        try {
            mapJakcson = mapper.writeValueAsString(form);
        } catch (JsonProcessingException e) {
            e.printStackTrace();
        }
        System.out.println(mapJakcson);
        //{"testConst":13}

 

fastjson method 1: enumeration inherits JSONSerializable

@AllArgsConstructor
public enum TestConst implements JSONSerializable {
    AFFIRM_STOCK(12) {
        @Override
        public void write(JSONSerializer jsonSerializer, Object o, Type type, int i) throws IOException {
            jsonSerializer.write(this.getStatus());
        }
    },

    CONFIRM_ORDER(13) {
        @Override
        public void write(JSONSerializer jsonSerializer, Object o, Type type, int i) throws IOException {
            jsonSerializer.write(this.getStatus());
        }
    },;

    @Setter
    @Getter
    private int status;


}

 

fastjson method 2: https://www.cnblogs.com/insaneXs/p/9515803.html