Write a function to realize the function of maketrans and convert two strings into a dictionary. The characters in the first string are keys and the characters in the second string are values

First string: 'abcmn' second string: 'one, two, three, four, five'

Results: {'a': 'one', 'b': 'two', 'c': 'three','m ':' four ',' n ':' five '}

def str_1(str1: str, str2: str):
    dict1 = {}
    for i in range(len(str1)):
        dict1[str1[i]] = str2[i]
    return dict1


dict1 = str_1('abcmn', 'one two three four five')
print(dict1)

Write your own join function to connect the elements in any sequence with the specified string into a new string

Sequence: [10, 20, 30, 'abc'] string: '+' result: '10+20+30+abc'

Sequence: 'abc' string: '–' result: 'a – b--c'

Note: the elements in the sequence can not be strings

def new_join(list1, str1):
    str2 = ''
    for i in list1[:-1]:
        str2 += str(i) + str1
    return str2 + list1[-1]
list1 = [10, 20, 30, 'abc']
str1 = '+'
str3 = new_join(list1, str1)
print(str3)

Write an input own upper function to judge whether the specified string is a pure uppercase string

'AMNDS' -> True

'amsKS' -> False

'123asd' -> False

def new_upper(str1):
    for i in str1:
        if not 'A' <= i <= 'Z':
            return False
    else:
        return True
str1 = 'AMNDS'
str2 = new_upper(str1)
print(str2)

Write a clear function to clear the specified list.

Note: the function is to clear the original list without generating a new list

def new_list(list1):
    for i in list1[0:]:
        del list1[0]
    return list1
list1 =  [10, 20, 30, 'abc']
list1 = new_list(list1)
print(list1)

Write a reverse function to reverse the elements in the list

Two methods: 1 Generate a new list 2 The order of the elements in the original list is directly modified without generating a new list

def new_list(list1):
    list2 = []
    for i in list1[::-1]:
        list2.append(i)
    return list2
list1 =  [10, 20, 30, 'abc']
list1 = new_list(list1)
print(list1)

Write a replace function to replace the specified substring in the string with a new substring

Original string: 'abc123abc ha ha uui123' old substring: '123' new substring: 'AB'

Results: 'abcbabc ha ha uuiAB'

def new_replace(str1, str2, str3):
    str4 = str1.split(str2)

    str5 =  str3.join(str4)

    return str5
str1 ='abc123abc Ha ha ha uui123'
str2 ='123'
str3 ='AB'
str = new_replace(str1, str2, str3)
print(str)

Write a function that can get the ten digits of any integer

123 -> 2

82339 -> 3

9 -> 0

-234 -> 3

def num_1(num1):
    x = num1 // 10 % 10
    return x

num = num_1(123)
print(num)

Write a function to realize the function of mathematical set operator & and find the common part of two sets:

Set 1: {1, 2, 3} set 2: {6, 7, 3, 9, 1}

Result: {1, 3}

def set_1(set1, set2):
    set3 = set()
    for i in set1:
        if i in set2:
            set3.add(i)
    return set3
set1 = {1, 2, 3}
set2 = {6, 7, 3, 9, 1}
s = set_1(set1, set2)
print(s)

Write a function to implement the function of its own dictionary update method, and add all the key value pairs in one dictionary to another dictionary

Dictionary 1: {a ': 10,' b ': 20} dictionary 2: {name': Zhang San, 'age': 18} - > the result turns Dictionary 1 into: {a ': 10,' b ': 20, name': Zhang San, 'age': 18}

Dictionary 1: {a ': 10,' b ': 20} dictionary 2: {a': 100, 'c': 200} - > the result makes Dictionary 1: {a ': 10,' b ': 20,' c ': 200}

def new_update(dict1, dict2):
    for key in dict2:
        dict1.setdefault(key, dict2[key])


    return dict1
dict1 = {'a': 10, 'b': 20}
dict2 = {'name': 'Zhang San', 'age': 18}
a = new_update(dict1, dict2)
print(a)

Write a function to judge whether the specified number is the number of daffodils

12321 -> True

2332 -> True

9876789 -> True

1232 -> False

def new_num(num):
    n = str(num)
    if n[:] == n[::-1]:
        return True
    else:
        return False


num = 1232
a = new_num(num)
print(a)

Write a function to judge whether the specified number is complete (more difficult)

Perfect: the sum of the true factors is equal to the number itself

For example, 6 is a perfect number, the truth factors of 6 are 1, 2 and 3, and 1 + 2 + 3 equals 6, so 6 is a perfect number

28 is the perfect number. The true factors of 28 are 1, 2, 4, 7 and 14. 1 + 2 + 4 + 7 + 14 equals 28, so 28 is the perfect number

12 is not perfect: the true factor of 12: 1, 2, 3, 4, 6, 1 + 2 + 3 + 4 + 6 is not equal to 12

def new_num(num):
    j = 0
    for i in range(1, num):
        if num % i == 0:
            j += i
    if j == num:
        return True
    else:
        return False


num = 21
print(new_num(num))