A Date Difference

Title Description

There are two dates. Find the number of days between the two dates. If the two dates are consecutive, we specify two days between them.

input

There are multiple sets of data, each with two rows representing two dates in the form of YYYYMMDD

output

Each set of data outputs a row, the date difference

sample input

20130101
20130105

sample output

5

Submit Code

#include<stdio.h>
int isprime(int n){
if((n%4==0&&n%100!=0)||n%400==0)
    return 1;
else
     return 0;
}
int main(){
  int num[13][2]={{0,0},{31,31},{28,29},{31,31},{30,30},{31,31},
  {30,30},{31,31},{31,31},{30,30},{31,31},{30,30},{31,31}};
  int a,b,t;
int y1,m1,d1,y2,m2,d2;
  while(scanf("%d %d",&a,&b)!=EOF){
    if(a>b){
    t=a;
    a=b;
    b=t;
  }
  y1=a/10000;m1=a%10000/100;d1=a%100;
  y2=b/10000;m2=b%10000/100;d2=b%100;
  int count=0;
  while(y1!=y2||m1!=m2||d1!=d2){
    d1++;
    if(d1==num[m1][isprime(y1)]+1){
       d1=1;
       m1++;
       }
    if(m1==13){
    m1=1;
    y1++;
    }
    count++;
 }
 printf("%d\n",count+1);
  }
  return 0;
}

B Day of Week

C Print Date

Title Description

Give the year minute m and the nth day of the year, and calculate what month the nth day is.

input

The input consists of two integers y (1<=y<=3000) and N (1<=n<=366).

output

There may be multiple sets of test data. For each set of data, print the corresponding date in the input in yyyy-mm-dd format.

sample input

2013 60
2012 300
2011 350
2000 211

sample output

2013-03-01
2012-10-26
2011-12-16
2000-07-29

Code Submission

#include <stdio.h>
#include <string.h>

int isprime(int n){
if((n%4==0&&n%100!=0)||n%400==0)
    return 1;
else
     return 0;
}
int main(){
	int month[13][2]={{0,0}, {31,31}, {28,29}, {31,31}, {30,30}, {31,31}, {30,30}, {31,31}, {31,31}, {30,30}, {31,31}, {30,30}, {31,31}};
	int y, m=1, d=0, n;
	while(scanf("%d%d", &y, &n)!=EOF){
		while(n>0){
			d++;
			if(d==month[m][isprime(y)]+1){
				m++;
				d=1;
			}
			if(m==13){
				y++;
				m=1;
			}
			n--;
		}
		printf("%04d-%02d-%02d\n", y, m, d);
		m=1, d=0;
	}
	return 0;
}

D Date Class

Title Description

Write a date class that requires the date to be output in XX xx-xx-xx format for an extra day operation.

input

Enter the first row to represent the number of test cases m, and the next M rows to have three integers separated by spaces representing the year, month and day. Test data will not have leap years.

output

Output m lines. Output in XX xx-xx-xx format, representing the day after the input date.

sample input

2
1999 10 20
2001 1 31

sample output

1999-10-21
2001-02-01

Tips

Note that there must be 0 before the digit date.

Code Submission

#include <stdio.h>
#include <string.h>

int isprime(int n){
if((n%4==0&&n%100!=0)||n%400==0)
    return 1;
else
     return 0;
}

int main()
{
	int num[13][2]={{0,0}, {31,31}, {28,29}, {31,31}, {30,30}, {31,31}, {30,30}, {31,31}, {31,31}, {30,30}, {31,31}, {30,30}, {31,31}};
	int year,month,day,days,m;
	while(scanf("%d",&m)!=EOF)
	{
		for(int i=0;i<m;i++)
	   {
		   scanf("%d%d%d", &year,&month,&day);

			if(day==num[month][isprime(year)]+1){
				month++;
				day=1;
			}
			if(month==13){
				year++;
				month=1;
			}
			day=day+1;
          printf("%04d-%02d-%02d\n", year,month,day);
       }
	}
	return 0;
}

E-Date Accumulation

Title Description

Design a program that calculates a date plus what date is after a few days.

input

Enter the first row to represent the number of samples m, and the next M rows to represent the year, month, day, and the cumulative number of days.

output

Output m lines, each output in the number of yyyy-m m-dd.

sample input

1
2008 2 3 100

sample output

2008-05-13

Code Submission

#include <stdio.h>
#include <string.h>

int isprime(int n){
if((n%4==0&&n%100!=0)||n%400==0)
    return 1;
else
     return 0;
}


int main()
{
    int num[13][2]={{0,0}, {31,31}, {28,29}, {31,31}, {30,30}, {31,31}, {30,30}, {31,31}, {31,31}, {30,30}, {31,31}, {30,30}, {31,31}};
    int day,year,month,cnt;
    int n;
    scanf("%d",&n);

    for(int j = 0;j < n;j++){
        scanf("%d %d %d %d",&year,&month,&day,&cnt);
        for(int i = cnt;i > 0;i--){
            day++;
            if(day==num[month][isprime(year)]+1){
                month++;
                day = 1;
            }
            if(month == 13){
                year++;
                month = 1;
            }
        }
        printf("%04d-%02d-%02d\n",year,month,day);
    }
    return 0;
}