Spring MVC file upload

1. Use maven to introduce two jar commons-io-2.6.jar commons-fileupload-1.3.3.jar based on Spring jar package and spring MVC jar package.

2. Spring MVC needs to configure processor mapper, processor adapter, view parser and automatic scanning in spring mvc.xml.

	<!-- To configure SpringMVC You need to configure the processor mapper, processor adapter, view parser, and scan the corresponding controller package -->
	<mvc:annotation-driven /><!--Configure processor mapper, processor adapter -->
	<bean
	class="org.springframework.web.servlet.view.InternalResourceViewResolver">
		<property name="prefix" value="/" />
		<property name="suffix" value=".jsp" />
	</bean>
	<context:component-scan base-package=""></context:component-scan>

3. For spring MVC file upload, you need to upload the configuration file in spring mvc.xml.

The specific configuration of SpringMVC.xml is as follows:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xmlns:context="http://www.springframework.org/schema/context"
	xmlns:mvc="http://www.springframework.org/schema/mvc"
	xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.3.xsd
		http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
		http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.3.xsd">

	<!-- To configure SpringMVC You need to configure the processor mapper, processor adapter, view parser, and scan the corresponding controller package -->
	<mvc:annotation-driven /><!--Configure processor mapper, processor adapter -->
	<bean	class="org.springframework.web.servlet.view.InternalResourceViewResolver">
		<property name="prefix" value="/" />
		<property name="suffix" value=".jsp" />
	</bean>
	<context:component-scan base-package=""></context:component-scan>
	<bean id="multipartResolver"
		class="org.springframework.web.multipart.commons.CommonsMultipartResolver">
		<property name="defaultEncoding" value="UTF-8"></property>
		<property name="maxUploadSize" value="1048576"></property>
	</bean>
	<!-- Static resources do not need to be intercepted -->
	<mvc:resources location="/" mapping="/**/*.*"></mvc:resources>
</beans>

4. web.xml configuration

<!-- To configure DispatcherServlet -->
	<servlet>
		<servlet-name>springDispatcherServlet</servlet-name>
		<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
		<init-param>
			<param-name>contextConfigLocation</param-name>
			<param-value>classpath:SpringMVC.xml</param-value>
		</init-param>
		<load-on-startup>1</load-on-startup>
	</servlet>
	<servlet-mapping>
		<servlet-name>springDispatcherServlet</servlet-name>
		<url-pattern>/</url-pattern>
	</servlet-mapping>


	<!-- Chinese garbled -->
	<filter>
		<filter-name>encodingFilter</filter-name>
		<filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
		<init-param>
			<param-name>encoding</param-name>
			<param-value>UTF-8</param-value>
		</init-param>
	</filter>
	<filter-mapping>
		<filter-name>encodingFilter</filter-name>
		<url-pattern>/*</url-pattern>
	</filter-mapping>

5. Write the UI interface fileUpload.jsp for file upload

• method="post" enctype="multipart/form-data" type="file"
  

6. Write FileUploadController

@Controller
public class FileUploadController {	
	//If the function parameter name is the same as the UI name, you do not need to configure @ RequestParam. Otherwise, the value value of @ RequestParam should be the same as the UI name.
	@RequestMapping("/fileUpload")
	public String upload(@RequestParam("fileUpload") MultipartFile file) throws Exception, IOException {
		//1. Get the file name
		String fileName=file.getOriginalFilename();
		String savePath="F://fileUpload";
		//1. Generally, the file is not saved on the project or server, but on the local disk.
		//2. The address path of the general file to be saved in the database. Generally, the content of the file is not saved.
		//3. It is better not to put all the files under one folder. You can create a folder and store the files according to certain rules.
		File filePath=new File(savePath);
		if(!filePath.exists()) {//Create file if file does not exist
			filePath.mkdir();//create folder
		}	
		//Destination address of the document
		File dest=new File(savePath+File.separator+fileName);
		System.out.println(savePath+File.separator+fileName);
		file.transferTo(dest);//Go to the file as dest
		return "success";
	}
}

Multi file upload

@RequestMapping("/fileUpload")
	public String upload(@RequestParam("fileUpload") MultipartFile files[]) throws Exception, IOException {
		String savePath = "F://fileUpload";
		File filePath = new File(savePath);
		if (!filePath.exists()) {// Create file if file does not exist
			filePath.mkdir();// create folder
		}
		for (MultipartFile file : files) {
			File dest = new File(savePath + File.separator + file.getOriginalFilename());
			System.out.println(savePath + File.separator + file.getOriginalFilename());
			file.transferTo(dest);
		}
		return "success";
	}