Practical analysis and summary of various binary vulnerability principles

This part will make a systematic analysis of common binary vulnerabilities to facilitate the location and identification of what types of vulnerabilities are in the process of vulnerability mining. If you want to do a good job, you must first sharpen its tools. catalogue 0x01 stack overflow vulnerability principle 0x02 heap overflow vulnerab ...

Posted by groundwar on Sun, 26 Dec 2021 22:42:39 +0100

Introduction to C language memory management

What is memory Macroscopically, the memory that stores data can be called memory. The memory discussed in this chapter is the memory for the program in program design. Memory is used to store data, which can be understood as arranged in boxes. Boxes are used to store data, but the boxes themselves have numbers and are continuous. This num ...

Posted by r3drain on Sun, 26 Dec 2021 19:52:19 +0100

2021.08. 09 [popularization group] simulation group C competition summary

2021.08. 09 [popularization group] simulation group C competition summary Write before: Today's exam is average. I didn't do very well. Continue to work hard next time! 😢😢😢 The mistake of this competition is that I didn't seriously read the meaning of the topic. Next time, I will continue to work hard! ok, let's start summarizing! ...

Posted by crosbystillsnas on Sun, 26 Dec 2021 17:48:26 +0100

C/C + + string function

unrestricted Length of string strlen(const char* s) Returns the string length until '\ 0' is encountered in s #define _CRT_SECURE_NO_WARNINGS 1 #include <stdio.h> #include <string.h> int main() { char str[10] = "Hello"; int len = strlen(str); printf("%d\n", len);//The calculated length is 5, and '\ 0' will not be cal ...

Posted by andysez on Sat, 25 Dec 2021 22:34:03 +0100

Algorithm - discretization

The discretization in this section refers in particular to the order preserving discretization of integers. What is 1 There is such a problem in processing: processing the number (eg.105) with a small number in a large data range (eg.0 ~ 109), that is, "large value range, small number". The large storage space and high time complexi ...

Posted by kpowning on Sat, 25 Dec 2021 22:08:30 +0100

[opencv] the role of Keys in CommandLineParser

I The role of CommandLineParser This class belongs to one of many classes in opencv, which is used to parse the command line. When (int argc,char** argv) in the main function receives the input parameter, it can parse the input command through CommandLineParser to make different responses. One of the advantages of this parsing class is that wh ...

Posted by e11even on Sat, 25 Dec 2021 19:45:06 +0100

C + + premier plus (Sixth Edition) Chapter 10 answers to object and class programming exercises

1. Provide method definitions for the classes described in review question 5, and write a small program to demonstrate all the features. This question examines the declaration, definition and simple use of classes. It is not difficult. The sample code is as follows: // account.h -- class defination for Account #ifndef ACCOUNT_H_ #define ACCOUNT ...

Posted by dannau on Sat, 25 Dec 2021 18:05:42 +0100

[C + + explanation] C + + exception handling | exception specification specifier

preface The noexcept keyword is an exception handling keyword for C + + only. stay Last In, we learned about exception throwing, catching and overloading. Consider the following questions: If a function (possibly from a third-party library) throws an exception, how do you know the type it may throw? Looking at the source code is indeed ...

Posted by erisande on Sat, 25 Dec 2021 16:30:47 +0100

PAT class a summary

PAT class a summary - Beginner Level 1, Mathematics It is often used as a basic 20 point sub topic in PAT. The change of the topic is relatively novel, but the basic idea remains the same. 1.1 prime Egyptian screening method: to obtain all primes within natural number n, the multiples of all primes not greater than root n must be eliminated ...

Posted by sissy on Sat, 25 Dec 2021 14:42:15 +0100

PAT (Advanced Level) Practice 1060 Are They Equal (25 points) Ling Chen 1642

PAT (Advanced Level) Practice 1060 Are They Equal (25 points) Ling Chen 1642 Title Description: If a machine can save only 3 significant digits, the float numbers 12300 and 12358.9 are considered equal since they are both saved as 0.123×105 with simple chopping. Now given the number of significant digits on a machine and two float numbers, yo ...

Posted by roygbiv on Sat, 25 Dec 2021 14:13:04 +0100